Answering Technique-Chemistry SPM (w Analysis)
Ps : regarding the 17 mark Planning of Experiment question in SPM Chemistry Paper 3. SPM Chemistry 2010 – Extra Tips and Predictions for Paper4541/3 In previous years, SPM Chemistry Paper 3 (2004-2009) has comprises of 2-3 questions with the last question typically comprise of “Planning of Experiment). Detailed information can be found from the list below: The last question (planning of experiment) of Paper 3 consists of 17 marks. Based on the analysis, the questions will be ask within the Form 4 or Form 5 syllabus (Can be recommended PEKA experiments or not PEKA experiments) (It is not only Form 4 as rumoured) The question will comprise of the following part such as: a) Statement of the problem (2003, 2005, 2007, 2009) BIT Paper 3 (SPM 2010) From above analysis, the predicted SPM 2010 last question in Paper 3 is: a) Aim of experiment Each section the maximum marks will be 3 marks (3 x 6 = 18 marks). But the marks provided is 17 marks, so this would depend on the marking scheme either 1 mark will be an extra point or one of the part (a) or (f) would be 2 marks. How to answer the question? a) Statement of the problem: It always must be a question and ended with question mark. Read the question well and you will find it in the hint in the question. Start your statement of the problem with ‘How does manipulated variable affect responding variable?’ or ‘Does increasing/decreasing manipulated variable increase/decrease the responding variable?’ b) Aim of experiment: It always must be a statement and ended with full stop. Start your aim of experiment with ‘To compare … / To investigate … / To study … c) All the variables: List out all the variables and separate each variable in the following sequence. d) Statement of the hypothesis: It always must be a statement and ended with full stop. ‘Themanipulated variable, the higher/lower/increase/decrease responding variable’ Important note: Must follow the sequence (always start with manipulated variable and follow by responding variable). e) List of substances and apparatus: Always separate substance and apparatus even though this is in one section. Must list everything completely to get 3 marks! Substances: (the same meaning with materials in PEKA experiments) Important note: Solution: try to give the concentration of the solution (always in the range of 0.1 – 1.0 mol dm-3) and concentrated solution (>1.0 mol dm-3) Example: Apparatus: try to list as complete as possible (everything that can be reused in the experiment) Example: f) Procedure of the experiment: This is the hardest part to get full marks (3 marks). You need to write the procedure as complete as possible which means all steps are to be written in detail. Berry Teacher would recommend the sentence should be written in passive form sentence (same in PEKA) and it can be present or past tense (no penalty). And try to uniform it. From the previous SPM Paper 3 record, there is no penalty if you write in active form sentence but not in PEKA report! g) Tabulation of data: This is the easiest part to get one mark, as long as you draw a table (empty table / box), you will be given at least one mark. Remember to write unit in the manipulated variable column and responding variable column! So there you go, all you need to know about the last question “Planning of an Experiment” for SPM Chemistry 2010 Paper 3. Do share this important tips/answering technique with all your friends.
b) Aim of experiment (2004, 2006, 2008)
c) All the variables (2003, 2005, 2006, 2007, 2008, 2009)
d) Statement of the hypothesis (2004, 2006, 2007, 2008, 2009)
e) List of substances and apparatus (2003, 2004, 2005, 2006, 2007, 2008, 2009)
f) Procedure of the experiment (2003, 2004, 2005, 2006, 2007, 2008, 2009)
g) Tabulation of data (2003, 2004, 2005, 2006, 2007, 2008, 2009)
b) All the variables
c) Statement of the hypothesis
d) List of substances and apparatus
e) Procedure of the experiment
f) Tabulation of data
